add
fun addDFGEdgesForMutuallyExclusiveBranchingExpression(n: Node, branchingExp: Node?, branchingDecl: Node?)
Connects the node n with the node branchingExp if present or with the node branchingDecl. The assumption is that only branchingExp or branchingDecl are present, e.g. C++.
Parameters
n
branching
branching