程序包 cn.taketoday.core.io

接口 ResourceFilter

函数接口:

这是一个函数接口, 因此可用作 lambda 表达式或方法引用的赋值目标。

@FunctionalInterface
public interface ResourceFilter

作者:

TODAY
2019-05-25 22:21

方法概要

修饰符和类型	方法	说明
boolean	accept(Resource resource)	Tests whether or not the specified abstract Resource name should be included in a name list.

方法详细资料

accept

boolean accept(Resource resource)
        throws IOException

Tests whether or not the specified abstract Resource name should be included in a name list.

参数:

resource - The Resource to be tested

返回:

true if and only if pathname should be included

抛出:

IOException